5x^2dy+x(x+y)DX=0

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Solution for 5x^2dy+x(x+y)DX=0 equation: 


Simplifying
5x2dy + x(x + y) * DX = 0

Reorder the terms for easier multiplication:
5dx2y + x * DX(x + y) = 0

Multiply x * DX
5dx2y + xDX(x + y) = 0
5dx2y + (x * xDX + y * xDX) = 0

Reorder the terms:
5dx2y + (xyDX + x2DX) = 0
5dx2y + (xyDX + x2DX) = 0

Solving
5dx2y + xyDX + x2DX = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-1xyDX' to each side of the equation.
5dx2y + xyDX + -1xyDX + x2DX = 0 + -1xyDX

Combine like terms: xyDX + -1xyDX = 0
5dx2y + 0 + x2DX = 0 + -1xyDX
5dx2y + x2DX = 0 + -1xyDX
Remove the zero:
5dx2y + x2DX = -1xyDX

Add '-1x2DX' to each side of the equation.
5dx2y + x2DX + -1x2DX = -1xyDX + -1x2DX

Combine like terms: x2DX + -1x2DX = 0
5dx2y + 0 = -1xyDX + -1x2DX
5dx2y = -1xyDX + -1x2DX

Divide each side by '5x2y'.
d = -0.2x-1DX + -0.2y-1DX

Simplifying
d = -0.2x-1DX + -0.2y-1DX

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